Enthuware

int [] [] array = {{0}, {0, 1}, {0, 1, 2}, {0, 1, 2, 3}, {0, 1, 2, 3, 4}};

Is it two dimensional array? if yes, how?

The above statement is equivalent to below steps:

int [][] a = new int[5][5];
a[0] = new int[1];
a[1] = new int[2];
a[2] = new int[3];
a[3] = new int[4];
a[4] = new int[5];

a[0][0] = 0;

a[1][0] = 0;
a[1][1] = 1;

a[2][0] = 0;
a[2][1] = 1;
a[2][2] = 2;

a[3][0] = 0;
a[3][1] = 1;
a[3][2] = 2;
a[3][4] = 3;

a[4][0] = 0;
a[4][1] = 1;
a[4][2] = 2;
a[4][4] = 3;
a[4][5] = 4;

Can you please correct me If I am wrong?

Why does it not compile though?
(I had selected option 1: 1 1)

This is a two dimensional array but the array pointed to by the variable arr1 is not. So arr1[4][1] cannot compile. This is explained in the explanation.

Oh.. Thank you!

This would be the case in which ArrayIndexOutOfBoundsException would be thrown? In what case would the IllegalArgumentException be thrown?

I get a compilation error on line "System.out.println (arr1[4][1]);"
Array type expected; found: 'int'

IrinaFF wrote: ↑

Sun Oct 20, 2019 5:01 am

I get a compilation error on line "System.out.println (arr1[4][1]);"
Array type expected; found: 'int'

Please post complete and exact code that you are trying to compile.