Enthuware

Why is B's m() not an override of A's m()? or am I looking at this question wrong?

the modifier is less restrictive.


//in file A.java
public class A
{
protected void m() throws SomeException{}
}

//in file B.java
public class B extends A
{
public void m(){ }
}

It is a valid override. The explanation doesn't say that it is not a valid override either. So I am not sure what is the problem?

-Paul.

Ok.

As I could see. We have 2 correct answers:

A a = new B();
a.m();


A a = new B();
( ( B) a ).m();

Am I right?

A a = new B();
a.m();

Did you read the explanation provided for this option? It explains exactly why this option is not correct.

A's m() declares 'throws SomeException', which is a checked exception, while the main() method doesn't. So a.m() must be wrapped in a try/catch block.