About Question enthuware.ocpjp.v8.2.1444 :

[bvrulez]

I was confused by the fact that the second option had an implemented method despite being abstract. But of course this is possible.

[Tester]

Could you give an example for

You can access d from a static inner class by using a reference to an instance of Outer.

If I understand right, I need to send an Outer's reference as a parameter to a method of the static Inner class, or?

[admin]

You do not necessarily need to send a reference as an argument. You can also do this:

Code: Select all

class Outer
{
    private double d = 10.0;

   static class SI {

    {
       System.out.println(new Outer().d);
    }

    void m(){
      System.out.println(new Outer().d);
    }
  }

}

[Tester]

Thank you a lot. It looks strange. You create new instance of Outer class. SI and method m() have different instances of Outer(). You may create any instance. There is no any connection between Outer and SI only name space. Sorry its not fully clear. Could you please give a link to clarify.
Thank you a lot one more time.

[admin]

In the example I showed above, I am accessing Outer's d from a static inner class. Yes, they are not same instances. If you want same Outer instance, of course you have to share that instance's reference some how. I am not sure which part is not clear to you and which link are you asking for.

[Tester]

You can access d from a static inner class by using a reference to an instance of Outer.

Static class does not have access to "this" (if i do not use DI, for example) it means that it does not have access to instance. If you create new instance it means that you have access to class and may create an instance. Please correct me if I wrong. I think now its clear. Thank you.

[admin]

We are talking about static inner class, so obviously, it has access to its enclosing class.